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Parse a list of s from input, and let selector list be the result.
I assume that :nth-child(odd of ul > li) should be invalid because ul > li is a , but :nth-child(odd of li.foo, li.bar) is valid because li.foo, li.bar is a .
I guess that this situation comes from the resolution and the commits mentionned in #1292 and #3760.
I suggest to replace S by and to define it as is identical to , except it parses its components as rather than . Selectors 5 can replace by if s become valid.
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The value definitions of
<:nth-child()>
and<:nth-last-child()>
includesS
defined as a
parsed as a forgiving selector list. But the first step of parsing as a forgiving selector list is:I assume that
:nth-child(odd of ul > li)
should be invalid becauseul > li
is a
, but:nth-child(odd of li.foo, li.bar)
is valid becauseli.foo, li.bar
is a
.I guess that this situation comes from the resolution and the commits mentionned in #1292 and #3760.
I suggest to replace
S
by
and to define it as
is identical to
, except it parses its components as
rather than
. Selectors 5 can replace
by
if
s become valid.The text was updated successfully, but these errors were encountered: