Implemented House Robber, DP

dynamic_programming/house_robber.py

@@ -0,0 +1,48 @@
+def house_robber(houses: list[int]) -> int:
+    """
+    Solves the House Robber problem using memoization (caching).
+    Returns the maximum amount of money that can be robbed without triggering alarms.
+    Problem URL: https://leetcode.com/problems/house-robber/
+
+    Args:
+        houses: A list of integers representing the amount of money in each house.
+    Returns:
+        int: The maximum amount of money that can be robbed without triggering alarms.
+    Raises:
+        ValueError: If there are no houses in the input list.
+
+    Examples:
+        >>> house_robber([2, 3, 2])
+        4
+        >>> house_robber([1, 2, 3, 1])
+        4
+        >>> house_robber([0, 0, 0, 0])
+        0
+        >>> house_robber([10, 15, 20, 25])
+        40
+        >>> house_robber([50])
+        50
+        >>> house_robber([5, 15, 5, 15, 5])
+        30
+    """
+    number_of_houses = len(houses)
+    if number_of_houses == 0:
+        raise ValueError("There must be at least one house")
+
+    memo = [-1 for _ in range(number_of_houses)]
+
+    def dp(n: int) -> int:
+        if n >= number_of_houses:
+            return 0
+        # If the house has been visited before, avoid revisiting (Memoization)
+        if memo[n] != -1:
+            return memo[n]
+
+        # Decide to rob this house and skip the next, or skip this one
+        rob = houses[n] + dp(n + 2)
+        dont_rob = dp(n + 1)
+
+        memo[n] = max(rob, dont_rob)
+        return memo[n]
+
+    return dp(0)