Pointers are all the same size, so it makes no practical difference, but
let's be tidy.
Found by Coverity, noted off-list by Tom Lane.
* buckets now and not have to keep track which tuples in the buckets have
* already been processed. We will free the old chunks as we go.
*/
- memset(hashtable->buckets, 0, sizeof(HashJoinTuple *) * hashtable->nbuckets);
+ memset(hashtable->buckets, 0, sizeof(HashJoinTuple) * hashtable->nbuckets);
oldchunks = hashtable->chunks;
hashtable->chunks = NULL;